What is expand (2n+3)/((n-1)n(n+1)) ?

The solution to expand (2n+3)/((n-1)n(n+1)) is (2n+3)/(n^3-n)

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expand (2n+3)/((n-1)n(n+1))

expand

\frac{2 n + 3}{( n - 1 ) n ( n + 1 )}

\frac{2 n + 3}{n ^{3} - n}

Solution steps

\frac{2 n + 3}{( n - 1 ) n ( n + 1 )}

Expand

(n - 1) n (n + 1) : n^{3} - n

= \frac{2 n + 3}{n ^{3} - n}

x \cdot y \cdot (4 - x^{2} - \frac{y ^{2}}{4})

sinh (3 (t - 5))

lo g_{10} (5) (8 x - 1)

(\frac{3}{2}) \cdot (\frac{3}{2}) \cdot (\frac{4}{2})

(x)^{\frac{1}{3}} ((x)^{2} - 4)

What is expand (2n+3)/((n-1)n(n+1)) ?
The solution to expand (2n+3)/((n-1)n(n+1)) is (2n+3)/(n^3-n)