What is ((6x)/7+3/10)((6x)/7-3/10) ?

The solution to ((6x)/7+3/10)((6x)/7-3/10) is ((60x+21)(60x-21))/(4900)

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simplify ((6x)/7+3/10)((6x)/7-3/10)

simplify

(\frac{6 x}{7} + \frac{3}{10}) (\frac{6 x}{7} - \frac{3}{10})

\frac{( 60 x + 21 ) ( 60 x - 21 )}{4900}

Solution steps

(\frac{6 x}{7} + \frac{3}{10}) (\frac{6 x}{7} - \frac{3}{10})

Join

\frac{6 x}{7} + \frac{3}{10} : \frac{60 x + 21}{70}

= \frac{60 x + 21}{70} (\frac{6 x}{7} - \frac{3}{10})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 60 x + 21 ) ( \frac{6 x}{7} - \frac{3}{10} )}{70}

Simplify

(60 x + 21) (\frac{6 x}{7} - \frac{3}{10}) : \frac{( 60 x + 21 ) ( 60 x - 21 )}{70}

= \frac{\frac{( 60 x + 21 ) ( 60 x - 21 )}{70}}{70}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 60 x + 21 ) ( 60 x - 21 )}{70 \cdot 70}

Multiply the numbers:

70 \cdot 70 = 4900

= \frac{( 60 x + 21 ) ( 60 x - 21 )}{4900}

\frac{π ^{3} y ^{4} + 2 y ^{2} + 2}{9 ( y ^{2} + 1 )}

(- \frac{3}{2}, - 2) y (9, \frac{3}{2})

- e^{- 0}

- e^{- 1}

What is ((6x)/7+3/10)((6x)/7-3/10) ?
The solution to ((6x)/7+3/10)((6x)/7-3/10) is ((60x+21)(60x-21))/(4900)