What are the solutions to the equation (x+2)^2=20 ?

The solutions to the equation (x+2)^2=20 are x=2sqrt(5)-2,x=-2sqrt(5)-2

Find the zeros of (x+2)^2=20

The zeros of (x+2)^2=20 are x=2sqrt(5)-2,x=-2sqrt(5)-2

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(x + 2)^{2} = 20

x = 25 - 2, x = - 25 - 2

Solution steps

(x + 2)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 20 : x = 25 - 2

Solve

x + 2 = - 20 : x = - 25 - 2

The solutions to the quadratic equation are:

x = 25 - 2, x = - 25 - 2

- 0.25

4 a^{3} - 7 a^{2} + 4 a - 7

y + 4 = 0

x^{2} + (x + 2)^{2} + 7 = (x + 4)^{2}

2 x + 2 = 0

What are the solutions to the equation (x+2)^2=20 ?
The solutions to the equation (x+2)^2=20 are x=2sqrt(5)-2,x=-2sqrt(5)-2
Find the zeros of (x+2)^2=20
The zeros of (x+2)^2=20 are x=2sqrt(5)-2,x=-2sqrt(5)-2