What is (2x^-3y^5)(3x^5y^2) ?

The solution to (2x^-3y^5)(3x^5y^2) is 3^2*2y^7x^5

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simplify (2x^-3y^5)(3x^5y^2)

simplify

(2 x^{-} 3 y^{5}) (3 x^{5} y^{2})

3^{2} \cdot 2 y^{7} x^{5}

Solution steps

(2 x^{-} \cdot 3 y^{5}) (3 x^{5} y^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3 \cdot 3 = 3^{1 + 1}

= 2 x^{-} y^{5} \cdot 3^{1 + 1} x^{5} y^{2}

Add the numbers:

1 + 1 = 2

= 2 x^{-} y^{5} \cdot 3^{2} x^{5} y^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{-} x^{5} = x^{-+ 5}

= 2 y^{5} \cdot 3^{2} x^{-+ 5} y^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{5} y^{2} = y^{5 + 2}

= 2 \cdot 3^{2} x^{-+ 5} y^{5 + 2}

Add the numbers:

5 + 2 = 7

= 2 \cdot 3^{2} x^{-+ 5} y^{7}

(- 1)^{3}

x^{2} (3 x^{3} y^{2})

\frac{e ^{2 x}}{e ^{3 x}}

f (x) = e^{- \frac{1}{x ^{2}}}

7 x^{5} y^{5} (14 x^{4} y^{2})

What is (2x^-3y^5)(3x^5y^2) ?
The solution to (2x^-3y^5)(3x^5y^2) is 3^2*2y^7x^5