What is (e^x-e^{-x})(e^x-e^{-x}) ?

The solution to (e^x-e^{-x})(e^x-e^{-x}) is (e^x-e^{-x})^2

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simplify (e^x-e^{-x})(e^x-e^{-x})

simplify

(e^{x} - e^{- x}) (e^{x} - e^{- x})

(e^{x} - e^{- x})^{2}

Solution steps

(e^{x} - e^{- x}) (e^{x} - e^{- x})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(e^{x} - e^{- x}) (e^{x} - e^{- x}) = (e^{x} - e^{- x})^{1 + 1}

= (e^{x} - e^{- x})^{1 + 1}

Add the numbers:

1 + 1 = 2

= (e^{x} - e^{- x})^{2}

(- 3)^{2}

- 4 x y^{3} (5 x y^{5})

(10 m^{5}) (5 m^{2})

2 x^{4} y^{3} (5 x)

f (x) = arccos (x)

What is (e^x-e^{-x})(e^x-e^{-x}) ?
The solution to (e^x-e^{-x})(e^x-e^{-x}) is (e^x-e^{-x})^2