What is t^2e^{-2x}cos(3t) ?

The solution to t^2e^{-2x}cos(3t) is (t^2cos(3t))/(e^{2x)}

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simplify t^2e^{-2x}cos(3t)

simplify

t^{2} e^{- 2 x} cos (3 t)

\frac{t ^{2} cos ( 3 t )}{e ^{2 x}}

Solution steps

t^{2} e^{- 2 x} cos (3 t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} t^{2} cos (3 t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot t ^{2} cos ( 3 t )}{e ^{2 x}}

Multiply:

1 \cdot t^{2} = t^{2}

= \frac{t ^{2} cos ( 3 t )}{e ^{2 x}}

x e^{- x} d x

x^{3} e^{- x^{2}}

(- 256 x^{5} y^{4}) e n t re (- 16 x^{8} y^{9})

e^{- l n ∣ y ∣}

What is t^2e^{-2x}cos(3t) ?
The solution to t^2e^{-2x}cos(3t) is (t^2cos(3t))/(e^{2x)}