What is simplify-x^2y^2(x^4-y^4+z^2-x^2y^2+y^2z^2) ?

The solution to simplify-x^2y^2(x^4-y^4+z^2-x^2y^2+y^2z^2) is -x^2y^2(-y^4+y^2z^2-x^2y^2+x^4+z^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify-x^2y^2(x^4-y^4+z^2-x^2y^2+y^2z^2)

simplify

- x^{2} y^{2} (x^{4} - y^{4} + z^{2} - x^{2} y^{2} + y^{2} z^{2})

- x^{2} y^{2} (- y^{4} + y^{2} z^{2} - x^{2} y^{2} + x^{4} + z^{2})

Solution steps

- x^{2} y^{2} (x^{4} - y^{4} + z^{2} - x^{2} y^{2} + y^{2} z^{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} y^{2} = (x y)^{2}

= - (x y)^{2} (- y^{4} + y^{2} z^{2} - x^{2} y^{2} + x^{4} + z^{2})

(x y)^{2} = x^{2} y^{2}

= - x^{2} y^{2} (- y^{4} + y^{2} z^{2} - x^{2} y^{2} + x^{4} + z^{2})

(- 1)^{x} (1)^{x}

(481) (4 - 64)

(4 x^{3}) (2 x^{4})

2 x (2 x)

\frac{x + 1}{x}

What is simplify-x^2y^2(x^4-y^4+z^2-x^2y^2+y^2z^2) ?
The solution to simplify-x^2y^2(x^4-y^4+z^2-x^2y^2+y^2z^2) is -x^2y^2(-y^4+y^2z^2-x^2y^2+x^4+z^2)