What are the solutions to the equation 0=x^2-5x-7 ?

The solutions to the equation 0=x^2-5x-7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2

Find the zeros of 0=x^2-5x-7

The zeros of 0=x^2-5x-7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2

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0 = x^{2} - 5 x - 7

x = \frac{5 + 53}{2}, x = \frac{5 - 53}{2}

Decimal Notation

x = 6.14005 \dots, x = - 1.14005 \dots

Solution steps

0 = x^{2} - 5 x - 7

Switch sides

x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 7) = 53

x_{1, 2} = \frac{- ( - 5 ) \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 53}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 53}{2 \cdot 1}

x = \frac{- ( - 5 ) + 53}{2 \cdot 1} : \frac{5 + 53}{2}

x = \frac{- ( - 5 ) - 53}{2 \cdot 1} : \frac{5 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 53}{2}, x = \frac{5 - 53}{2}

2 (6 + 10)

x^{2} + 2 x + 1 = 0

\frac{3}{2 \frac{2}{3}}

63 + 45 b

x^{4} + 6 x^{2} + 9

What are the solutions to the equation 0=x^2-5x-7 ?
The solutions to the equation 0=x^2-5x-7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2
Find the zeros of 0=x^2-5x-7
The zeros of 0=x^2-5x-7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2