What is 2/(sqrt(x))x^{-1} ?

The solution to 2/(sqrt(x))x^{-1} is 2/(sqrt(x)x)

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simplify 2/(sqrt(x))x^{-1}

simplify

\frac{2}{x} x^{- 1}

\frac{2}{x x}

Solution steps

\frac{2}{x} x^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{- 1} = \frac{1}{x}

= \frac{2}{x} \cdot \frac{1}{x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 1}{x x}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2}{x x}

\frac{81}{256}

\frac{x ^{x}}{( x + 1 ) ^{x}}

9 \cdot 1 0^{- 9}

- 2 x y^{2} (5 x y^{2})