What is (\sqrt[3]{x^3y^2})^{12} ?

The solution to (\sqrt[3]{x^3y^2})^{12} is x^{12}y^8

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simplify (\sqrt[3]{x^3y^2})^{12}

simplify

x^{12} y^{8}

Solution steps

Rewrite

12

3 \cdot 4

Apply exponent rule:

a^{b c} = (a^{b})^{c},

assuming

a \geq 0

Apply exponent rule:

assuming

n i s o dd or a \geq 0

= (x^{3} y^{2})^{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(x^{3} y^{2})^{4} = (x^{3})^{4} (y^{2})^{4}

= (x^{3})^{4} (y^{2})^{4}

Simplify

(x^{3})^{4} : x^{12}

= x^{12} (y^{2})^{4}

Simplify

(y^{2})^{4} : y^{8}

= x^{12} y^{8}

2 \times 23

e^{- x}

e^{- 2 t} cos (t)

(x + y)^{5}

\frac{- 81}{- 9}

What is (\sqrt[3]{x^3y^2})^{12} ?
The solution to (\sqrt[3]{x^3y^2})^{12} is x^{12}y^8