What is expand log_{7}(H^2)J^{11}K^{-5} ?

The solution to expand log_{7}(H^2)J^{11}K^{-5} is (2J^{11}log_{7}(H))/(K^5)

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expand log_{7}(H^2)J^{11}K^{-5}

expand

lo g_{7} (H^{2}) J^{11} K^{- 5}

\frac{2 J ^{11} lo g _{7} ( H )}{K ^{5}}

Solution steps

lo g_{7} (H^{2}) J^{11} K^{- 5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{K ^{5}} J^{11} lo g_{7} (H^{2})

Simplify

lo g_{7} (H^{2}) : 2 lo g_{7} (H)

= 2 \cdot \frac{1}{K ^{5}} J^{11} lo g_{7} (H)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 lo g _{7} ( H ) J ^{11}}{K ^{5}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 J ^{11} lo g _{7} ( H )}{K ^{5}}

12^{2}

e^{- 4.5}

(2.3 \cdot 1 0^{- 3}) (4.2 \cdot 1 0^{2})

(- 9)^{2}

What is expand log_{7}(H^2)J^{11}K^{-5} ?
The solution to expand log_{7}(H^2)J^{11}K^{-5} is (2J^{11}log_{7}(H))/(K^5)