What is (2/5)^{-3}left(3/7)^{-3} ?

The solution to (2/5)^{-3}left(3/7)^{-3} is (42875elft)/(216)

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simplify (2/5)^{-3}left(3/7)^{-3}

simplify

(\frac{2}{5})^{- 3} l e f t (\frac{3}{7})^{- 3}

\frac{42875 e l f t}{216}

Solution steps

(\frac{2}{5})^{- 3} l e f t (\frac{3}{7})^{- 3}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

(\frac{2}{5})^{- 3} (\frac{3}{7})^{- 3} = (\frac{2}{5} \cdot \frac{3}{7})^{- 3}

= e (\frac{2}{5} \cdot \frac{3}{7})^{- 3} l f t

\frac{2}{5} \cdot \frac{3}{7} = \frac{6}{35}

= e (\frac{6}{35})^{- 3} l f t

(\frac{6}{35})^{- 3} = \frac{3 5 ^{3}}{6 ^{3}}

= e \frac{3 5 ^{3}}{6 ^{3}} l f t

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 5 ^{3} l e f t}{6 ^{3}}

Refine

= \frac{42875 e l f t}{216}

(23) (35)

(2 x^{3}) l e f t (5 x^{3})

4 x e^{- 3 x}

1.4 \cdot 1 0^{- 4}

What is (2/5)^{-3}left(3/7)^{-3} ?
The solution to (2/5)^{-3}left(3/7)^{-3} is (42875elft)/(216)