What are the solutions to the equation x^2+3=0 ?

The solutions to the equation x^2+3=0 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^2+3=0

The zeros of x^2+3=0 are x=sqrt(3)i,x=-sqrt(3)i

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x^{2} + 3 = 0

x = 3 i, x = - 3 i

Solution steps

x^{2} + 3 = 0

Move

3

to the right side

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

\frac{n ^{\frac{3}{5}}}{n - \frac{3}{4}}

- 5 x + 6 = - 12 x + 62

2^{\frac{5}{3}}

x^{2} + 2 x \geq 8

- \frac{3}{x + 1} < \frac{1}{2 - x}

What are the solutions to the equation x^2+3=0 ?
The solutions to the equation x^2+3=0 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^2+3=0
The zeros of x^2+3=0 are x=sqrt(3)i,x=-sqrt(3)i