What are the solutions to the equation 800x-2x^2=0 ?

The solutions to the equation 800x-2x^2=0 are x=0,x=400

Find the zeros of 800x-2x^2=0

The zeros of 800x-2x^2=0 are x=0,x=400

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800 x - 2 x^{2} = 0

x = 0, x = 400

Solution steps

800 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 800 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 800 \pm 80 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

80 0^{2} - 4 (- 2) \cdot 0 = 800

x_{1, 2} = \frac{- 800 \pm 800}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 800 + 800}{2 ( - 2 )}, x_{2} = \frac{- 800 - 800}{2 ( - 2 )}

x = \frac{- 800 + 800}{2 ( - 2 )} : 0

x = \frac{- 800 - 800}{2 ( - 2 )} : 400

The solutions to the quadratic equation are:

x = 0, x = 400

10 x + 24 - 7 + 35 x = - 5 x + 67

\frac{125 x ^{4} y ^{3}}{x ^{5} y ^{7}}

3 x^{2} - 24 = 0

\frac{3 ^{3}}{4}

What are the solutions to the equation 800x-2x^2=0 ?
The solutions to the equation 800x-2x^2=0 are x=0,x=400
Find the zeros of 800x-2x^2=0
The zeros of 800x-2x^2=0 are x=0,x=400