What is (3x^ay)(7xy^b) ?

The solution to (3x^ay)(7xy^b) is 21x^{a+1}y^{b+1}

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simplify (3x^ay)(7xy^b)

simplify

(3 x^{a} y) (7 x y^{b})

21 x^{a + 1} y^{b + 1}

Solution steps

(3 x^{a} y) (7 x y^{b})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{a} x = x^{a + 1}

= 3 y \cdot 7 x^{a + 1} y^{b}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y y^{b} = y^{1 + b}

= 3 \cdot 7 x^{a + 1} y^{1 + b}

Multiply the numbers:

3 \cdot 7 = 21

= 21 x^{a + 1} y^{b + 1}

e^{- e^{- x}}

(27)^{3}

((2^{2})^{3})^{2}

3.7 \cdot 1 0^{- 3}