What are the solutions to the equation x^2+3x-180=0 ?

The solutions to the equation x^2+3x-180=0 are x=12,x=-15

Find the zeros of x^2+3x-180=0

The zeros of x^2+3x-180=0 are x=12,x=-15

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x^{2} + 3 x - 180 = 0

x = 12, x = - 15

Solution steps

x^{2} + 3 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 180 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 180) = 27

x_{1, 2} = \frac{- 3 \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 27}{2 \cdot 1}, x_{2} = \frac{- 3 - 27}{2 \cdot 1}

x = \frac{- 3 + 27}{2 \cdot 1} : 12

x = \frac{- 3 - 27}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 12, x = - 15

3 a b^{2} + 6 a^{2} c

0.0001 (500)^{3} + 0.005 (500)^{2} + 28 (500) + 3000

12 - y > y - 12

\frac{7 x}{8} + 9 = \frac{x}{2} + 6

4 (y + 1) + y = 5 (y - 1) + 9

What are the solutions to the equation x^2+3x-180=0 ?
The solutions to the equation x^2+3x-180=0 are x=12,x=-15
Find the zeros of x^2+3x-180=0
The zeros of x^2+3x-180=0 are x=12,x=-15