What is expand sqrt(((3x-4)(3-2x))/(4x^2-1)) ?

The solution to expand sqrt(((3x-4)(3-2x))/(4x^2-1)) is (sqrt((3x-4)(-2x+3)))/(sqrt(4x^2-1))

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expand sqrt(((3x-4)(3-2x))/(4x^2-1))

expand

\frac{( 3 x - 4 ) ( 3 - 2 x )}{4 x ^{2} - 1}

\frac{( 3 x - 4 ) ( - 2 x + 3 )}{4 x ^{2} - 1}

Solution steps

\frac{( 3 x - 4 ) ( 3 - 2 x )}{4 x ^{2} - 1}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}

\frac{( 3 x - 4 ) ( 3 - 2 x )}{4 x ^{2} - 1} = \frac{( 3 x - 4 ) ( 3 - 2 x )}{4 x ^{2} - 1}

= \frac{( 3 x - 4 ) ( - 2 x + 3 )}{4 x ^{2} - 1}

\frac{13}{3}

e^{- l n ∣ x ∣}

(e^{- a x^{2}})^{2}

4^{2 a}

What is expand sqrt(((3x-4)(3-2x))/(4x^2-1)) ?
The solution to expand sqrt(((3x-4)(3-2x))/(4x^2-1)) is (sqrt((3x-4)(-2x+3)))/(sqrt(4x^2-1))