What is the first (e^{x^2})^' ?

The first (e^{x^2})^' is e^{x^2}*2x

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(e^{x^2})^'

(e^{x^{2}})^{^{'}}

e^{x^{2}} \cdot 2 x

Solution steps

(e^{x^{2}})^{'}

Apply the chain rule:

e^{x^{2}} (x^{2})^{'}

= e^{x^{2}} (x^{2})^{'}

(x^{2})^{'} = 2 x

= e^{x^{2}} \cdot 2 x

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