What are the solutions to the equation 9-2x-x^2=0 ?

The solutions to the equation 9-2x-x^2=0 are x=-1-sqrt(10),x=sqrt(10)-1

Find the zeros of 9-2x-x^2=0

The zeros of 9-2x-x^2=0 are x=-1-sqrt(10),x=sqrt(10)-1

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9 - 2 x - x^{2} = 0

x = - 1 - 10, x = 10 - 1

Solution steps

9 - 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 9 = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2 10}{2 ( - 1 )} : - 1 - 10

x = \frac{- ( - 2 ) - 2 10}{2 ( - 1 )} : 10 - 1

The solutions to the quadratic equation are:

x = - 1 - 10, x = 10 - 1

\frac{x ^{2} + x - 42}{x} \geq 0

x^{2} + 2 x - e^{3} = 0

3 x - 10 = 5

2 - 4 x > 6

(\frac{1}{2})^{2} - 3

What are the solutions to the equation 9-2x-x^2=0 ?
The solutions to the equation 9-2x-x^2=0 are x=-1-sqrt(10),x=sqrt(10)-1
Find the zeros of 9-2x-x^2=0
The zeros of 9-2x-x^2=0 are x=-1-sqrt(10),x=sqrt(10)-1