What is ((f^{-1/6})^{6/5})^{-1} ?

The solution to ((f^{-1/6})^{6/5})^{-1} is f^{1/5}

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simplify ((f^{-1/6})^{6/5})^{-1}

simplify

((f^{- \frac{1}{6}})^{\frac{6}{5}})^{- 1}

f^{\frac{1}{5}}

Solution steps

((f^{- \frac{1}{6}})^{\frac{6}{5}})^{- 1}

(f^{- \frac{1}{6}})^{\frac{6}{5}} : f^{- \frac{1}{5}}

= (f^{- \frac{1}{5}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{f ^{- \frac{1}{5}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

f^{- \frac{1}{5}} = \frac{1}{f ^{\frac{1}{5}}}

= \frac{1}{\frac{1}{f ^{\frac{1}{5}}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{f ^{\frac{1}{5}}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= f^{\frac{1}{5}}

4 - x^{2} \cdot 1 + x

\frac{( k + 1 ) ^{2}}{k ^{2}}

e^{- 2 t} e^{- 2 t}

728.9 correc tt o^{4}

What is ((f^{-1/6})^{6/5})^{-1} ?
The solution to ((f^{-1/6})^{6/5})^{-1} is f^{1/5}