What is n^{2/3}m^{1/3}p^{2/3} ?

The solution to n^{2/3}m^{1/3}p^{2/3} is m^{1/3}(np)^{2/3}

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simplify n^{2/3}m^{1/3}p^{2/3}

simplify

n^{\frac{2}{3}} m^{\frac{1}{3}} p^{\frac{2}{3}}

m^{\frac{1}{3}} (n p)^{\frac{2}{3}}

Solution steps

n^{\frac{2}{3}} m^{\frac{1}{3}} p^{\frac{2}{3}}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

n^{\frac{2}{3}} p^{\frac{2}{3}} = (n p)^{\frac{2}{3}}

= m^{\frac{1}{3}} (n p)^{\frac{2}{3}}

x^{2} (x + 3)^{2} (x - 6) (x - 4)

e^{t} \cdot e^{- s t}

3 e^{- 0.02}

What is n^{2/3}m^{1/3}p^{2/3} ?
The solution to n^{2/3}m^{1/3}p^{2/3} is m^{1/3}(np)^{2/3}