What is (2/5)^{-3}e(3/7)^{-3} ?

The solution to (2/5)^{-3}e(3/7)^{-3} is (42875e)/(216)

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simplify (2/5)^{-3}e(3/7)^{-3}

simplify

(\frac{2}{5})^{- 3} e (\frac{3}{7})^{- 3}

\frac{42875 e}{216}

Decimal Notation

539.56635 \dots

Solution steps

(\frac{2}{5})^{- 3} e (\frac{3}{7})^{- 3}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

(\frac{2}{5})^{- 3} (\frac{3}{7})^{- 3} = (\frac{2}{5} \cdot \frac{3}{7})^{- 3}

= e (\frac{2}{5} \cdot \frac{3}{7})^{- 3}

\frac{2}{5} \cdot \frac{3}{7} = \frac{6}{35}

= e (\frac{6}{35})^{- 3}

(\frac{6}{35})^{- 3} = \frac{3 5 ^{3}}{6 ^{3}}

= e \frac{3 5 ^{3}}{6 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 5 ^{3} e}{6 ^{3}}

3 5^{3} = 42875

= \frac{42875 e}{6 ^{3}}

6^{3} = 216

= \frac{42875 e}{216}

(18 x^{3} y^{2} z^{5}) \times (6 x^{3} y z^{2})

e^{- t} \cdot sin (t)

e^{- 3.5}

(x + y) (x + y)

x^{2} + 1 x^{2} - 1

What is (2/5)^{-3}e(3/7)^{-3} ?
The solution to (2/5)^{-3}e(3/7)^{-3} is (42875e)/(216)