What is (2.87*10^{-10})^{12}*0.141*10^{-21} ?

The solution to (2.87*10^{-10})^{12}*0.141*10^{-21} is (4.40354E15)/(100000000000*10^{141)}

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simplify (2.8710^{-10})^{12}0.141*10^{-21}

simplify

(2.87 \cdot 1 0^{- 10})^{12} \cdot 0.141 \cdot 1 0^{- 21}

\frac{4.40354 E 15}{100000000000 \cdot 1 0 ^{141}}

Decimal Notation

4.40354 E - 137

Solution steps

(2.87 \cdot 1 0^{- 10})^{12} \cdot 0.141 \cdot 1 0^{- 21}

(2.87 \cdot 1 0^{- 10})^{12} = \frac{3.12308 E 15}{10000000000 \cdot 1 0 ^{120}}

= \frac{3.12308 E 15}{10000000000 \cdot 1 0 ^{120}} \cdot 0.141 \cdot 1 0^{- 21}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 21} = \frac{1}{1 0 ^{21}}

= \frac{3.12308 E 15}{10000000000 \cdot 1 0 ^{120}} \cdot 0.141 \cdot \frac{1}{1 0 ^{21}}

\frac{3.12308 E 15}{10000000000 \cdot 1 0 ^{120}} \cdot 0.141 \cdot \frac{1}{1 0 ^{21}} = \frac{4.40354 E 14}{1 0 ^{141} \cdot 10000000000}

= \frac{4.40354 E 14}{1 0 ^{141} \cdot 10000000000}

\frac{4.40354 E 14}{1 0 ^{141} \cdot 10000000000} = \frac{4.40354 E 15}{100000000000 \cdot 1 0 ^{141}}

= \frac{4.40354 E 15}{100000000000 \cdot 1 0 ^{141}}

(e^{x}) e^{x}

(x^{2} + 8 x - 84) e^{- 3.25 x}

(6 + 5) (6 + 5)

What is (2.87*10^{-10})^{12}*0.141*10^{-21} ?
The solution to (2.87*10^{-10})^{12}*0.141*10^{-21} is (4.40354E15)/(100000000000*10^{141)}