What is x^2(x^3+1)^2(4x^2+1)(3x-4) ?

The solution to x^2(x^3+1)^2(4x^2+1)(3x-4) is x^2(3x-4)(x^3+1)^2(4x^2+1)

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simplify x^2(x^3+1)^2(4x^2+1)(3x-4)

simplify

x^{2} (x^{3} + 1)^{2} (4 x^{2} + 1) (3 x - 4)

x^{2} (3 x - 4) (x^{3} + 1)^{2} (4 x^{2} + 1)

Solution steps

x^{2} (x^{3} + 1)^{2} (4 x^{2} + 1) (3 x - 4)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} (x^{3} + 1)^{2} = (x (x^{3} + 1))^{2}

= (x (x^{3} + 1))^{2} (4 x^{2} + 1) (3 x - 4)

(x (x^{3} + 1))^{2} = x^{2} (x^{3} + 1)^{2}

= x^{2} (x^{3} + 1)^{2} (4 x^{2} + 1) (3 x - 4)

6 e^{- 2}

6 e^{- 0}

\frac{4 + x}{y - 1}

e^{y} \cdot e^{x}

5.2 \cdot 1 0^{- 2}

What is x^2(x^3+1)^2(4x^2+1)(3x-4) ?
The solution to x^2(x^3+1)^2(4x^2+1)(3x-4) is x^2(3x-4)(x^3+1)^2(4x^2+1)