What are the solutions to the equation 4x^2+8x=10 ?

The solutions to the equation 4x^2+8x=10 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

Find the zeros of 4x^2+8x=10

The zeros of 4x^2+8x=10 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 8 x = 10

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

Decimal Notation

x = 0.87082 \dots, x = - 2.87082 \dots

Solution steps

4 x^{2} + 8 x = 10

Move

10

to the left side

4 x^{2} + 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 10) = 414

x_{1, 2} = \frac{- 8 \pm 4 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 14}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 14}{2 \cdot 4}

x = \frac{- 8 + 4 14}{2 \cdot 4} : \frac{- 2 + 14}{2}

x = \frac{- 8 - 4 14}{2 \cdot 4} : - \frac{2 + 14}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

3 \leq x - 5

x^{2} + 13 < 6 x

x^{2} - 7 x \leq - 12

- 2 p - 9 < 2 (p - 10) + 5

(36) (22)

What are the solutions to the equation 4x^2+8x=10 ?
The solutions to the equation 4x^2+8x=10 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2
Find the zeros of 4x^2+8x=10
The zeros of 4x^2+8x=10 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2