What is sqrt(\sqrt[3]{9a^4b^2)} ?

The solution to sqrt(\sqrt[3]{9a^4b^2)} is cube root of 3}\sqrt[6]{a^4b^2

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simplify sqrt(\sqrt[3]{9a^4b^2)}

simplify

Solution steps

Apply radical rule:

= ((9 a^{4} b^{2})^{\frac{1}{3}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (9 a^{4} b^{2})^{\frac{1}{3} \cdot \frac{1}{2}}

\frac{1}{3} \cdot \frac{1}{2} = \frac{1}{6}

= (9 a^{4} b^{2})^{\frac{1}{6}}

Apply radical rule:

assuming

a \geq 0, b \geq 0

(9^{l o g_{9} (π)})^{3.8}

e^{3 x} \times e^{3 x}

(43) (53)

7^{2 m} \cdot 6^{2 m}

(- 2)^{n} (- \frac{1}{2})^{n}

What is sqrt(\sqrt[3]{9a^4b^2)} ?
The solution to sqrt(\sqrt[3]{9a^4b^2)} is cube root of 3}\sqrt[6]{a^4b^2