What is (\sqrt[5]{y^2x^{-3}})x^{-3}y^{-1} ?

The solution to (\sqrt[5]{y^2x^{-3}})x^{-3}y^{-1} is (\sqrt[5]{y^2})/(\sqrt[5]{x^3)x^3y}

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simplify (\sqrt[5]{y^2x^{-3}})x^{-3}y^{-1}

simplify

Solution steps

Apply rule:

(a) = a

Simplify

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 3} = \frac{1}{x ^{3}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

y^{- 1} = \frac{1}{y}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

Simplify

(4.3 \times 1 0^{2}) \times (4 \times 1 0^{- 3})

1 0^{- 7}

(37)^{2}

(3 x^{2}) (4 x)

x e^{- x^{2}} d x

What is (\sqrt[5]{y^2x^{-3}})x^{-3}y^{-1} ?
The solution to (\sqrt[5]{y^2x^{-3}})x^{-3}y^{-1} is (\sqrt[5]{y^2})/(\sqrt[5]{x^3)x^3y}