What is e^{-2}((2s^2-6s+5)/(s^3-6s^2+11s-6)) ?

The solution to e^{-2}((2s^2-6s+5)/(s^3-6s^2+11s-6)) is (2s^2-6s+5)/(e^2(s^3-6s^2+11s-6))

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simplify e^{-2}((2s^2-6s+5)/(s^3-6s^2+11s-6))

simplify

e^{- 2} (\frac{2 s ^{2} - 6 s + 5}{s ^{3} - 6 s ^{2} + 11 s - 6})

\frac{2 s ^{2} - 6 s + 5}{e ^{2} ( s ^{3} - 6 s ^{2} + 11 s - 6 )}

Solution steps

e^{- 2} (\frac{2 s ^{2} - 6 s + 5}{s ^{3} - 6 s ^{2} + 11 s - 6})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2}} \cdot \frac{2 s ^{2} - 6 s + 5}{s ^{3} - 6 s ^{2} + 11 s - 6}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( 2 s ^{2} - 6 s + 5 )}{e ^{2} ( s ^{3} - 6 s ^{2} + 11 s - 6 )}

1 \cdot (2 s^{2} - 6 s + 5) = 2 s^{2} - 6 s + 5

= \frac{2 s ^{2} - 6 s + 5}{e ^{2} ( s ^{3} - 6 s ^{2} + 11 s - 6 )}

(x + 5)^{2} (x - 7)^{2}

t e^{a t} cos (b) t

\frac{- 18}{6}

e^{- \frac{∣ t ∣}{2}}

What is e^{-2}((2s^2-6s+5)/(s^3-6s^2+11s-6)) ?
The solution to e^{-2}((2s^2-6s+5)/(s^3-6s^2+11s-6)) is (2s^2-6s+5)/(e^2(s^3-6s^2+11s-6))