What is t^2e^{-2xcos(3t)} ?

The solution to t^2e^{-2xcos(3t)} is (t^2)/(e^{2xcos(3t))}

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simplify t^2e^{-2xcos(3t)}

simplify

t^{2} e^{- 2 x c o s (3 t)}

\frac{t ^{2}}{e ^{2 x c o s (3 t)}}

Solution steps

t^{2} e^{- 2 x c o s (3 t)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x c o s (3 t)}} t^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot t ^{2}}{e ^{2 x c o s (3 t)}}

Multiply:

1 \cdot t^{2} = t^{2}

= \frac{t ^{2}}{e ^{2 x c o s (3 t)}}

2 t e^{- t}

\frac{- 75}{3}

f (x) = (e^{x})^{\frac{1}{2}}

w^{2} e^{- 2}

\frac{- 32}{2}

What is t^2e^{-2xcos(3t)} ?
The solution to t^2e^{-2xcos(3t)} is (t^2)/(e^{2xcos(3t))}