What is \sqrt[3]{36^2} ?

The solution to \sqrt[3]{36^2} is 6\sqrt[3]{6}

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simplify \sqrt[3]{36^2}

simplify

Decimal Notation

10.90272 \dots

Solution steps

3 6^{2} = 1296

Prime factorization of

1296 : 2^{4} \cdot 3^{4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{4} \cdot 3^{4} = 2^{3} \cdot 2 \cdot 3^{3} \cdot 3

Apply radical rule:

Multiply the numbers:

2 \cdot 3 = 6

(- 9)^{2}

e^{- n^{2}}

t^{2} \cdot e^{- s t}

\frac{1 + x}{1 - x}

(\frac{2}{3})^{2} e^{- 3 (\frac{2}{3})}