What are the solutions to the equation 3x^2-38x+99=0 ?

The solutions to the equation 3x^2-38x+99=0 are x=9,x= 11/3

Find the zeros of 3x^2-38x+99=0

The zeros of 3x^2-38x+99=0 are x=9,x= 11/3

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3 x^{2} - 38 x + 99 = 0

x = 9, x = \frac{11}{3}

Decimal Notation

x = 9, x = 3.66666 \dots

Solution steps

3 x^{2} - 38 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 3 \cdot 99}{2 \cdot 3}

(- 38)^{2} - 4 \cdot 3 \cdot 99 = 16

x_{1, 2} = \frac{- ( - 38 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 38 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 38 ) - 16}{2 \cdot 3}

x = \frac{- ( - 38 ) + 16}{2 \cdot 3} : 9

x = \frac{- ( - 38 ) - 16}{2 \cdot 3} : \frac{11}{3}

The solutions to the quadratic equation are:

x = 9, x = \frac{11}{3}

x^{4} - 10 x^{2} + 24

(x^{2} - 5)^{2} - 3 (x^{2} - 5) - 4

ln (- 12)

2 x^{3} + 128 y^{3}

- 6 \cdot (- \frac{7}{2})

What are the solutions to the equation 3x^2-38x+99=0 ?
The solutions to the equation 3x^2-38x+99=0 are x=9,x= 11/3
Find the zeros of 3x^2-38x+99=0
The zeros of 3x^2-38x+99=0 are x=9,x= 11/3