What is (t-y)(1-t+y)^2(1-y)^2 ?

The solution to (t-y)(1-t+y)^2(1-y)^2 is (-y+1)^2(t-y)(y+1-t)^2

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simplify (t-y)(1-t+y)^2(1-y)^2

simplify

(t - y) (1 - t + y)^{2} (1 - y)^{2}

(- y + 1)^{2} (t - y) (y + 1 - t)^{2}

Solution steps

(t - y) (1 - t + y)^{2} (1 - y)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(y + 1 - t)^{2} (- y + 1)^{2} = ((y + 1 - t) (- y + 1))^{2}

= (t - y) ((y + 1 - t) (- y + 1))^{2}

((1 - t + y) (1 - y))^{2} = (1 - t + y)^{2} (1 - y)^{2}

= (t - y) (y + 1 - t)^{2} (- y + 1)^{2}

4.51 \cdot 1 0^{- 6}

(3)^{4}

1 + sin (x) \cdot 1 - sin (x)

- (5)^{2}

(64 x^{4})^{0.5} \cdot 4 x^{- 2}

What is (t-y)(1-t+y)^2(1-y)^2 ?
The solution to (t-y)(1-t+y)^2(1-y)^2 is (-y+1)^2(t-y)(y+1-t)^2