What are the solutions to the equation 7p^2=-6p+3 ?

The solutions to the equation 7p^2=-6p+3 are p=(-3+sqrt(30))/7 ,p=-(3+sqrt(30))/7

Find the zeros of 7p^2=-6p+3

The zeros of 7p^2=-6p+3 are p=(-3+sqrt(30))/7 ,p=-(3+sqrt(30))/7

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7 p^{2} = - 6 p + 3

p = \frac{- 3 + 30}{7}, p = - \frac{3 + 30}{7}

Decimal Notation

p = 0.35388 \dots, p = - 1.21103 \dots

Solution steps

7 p^{2} = - 6 p + 3

Move

3

to the left side

7 p^{2} - 3 = - 6 p

Move

6 p

to the left side

7 p^{2} - 3 + 6 p = 0

Write in the standard form

a x^{2} + b x + c = 0

7 p^{2} + 6 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

6^{2} - 4 \cdot 7 (- 3) = 230

p_{1, 2} = \frac{- 6 \pm 2 30}{2 \cdot 7}

Separate the solutions

p_{1} = \frac{- 6 + 2 30}{2 \cdot 7}, p_{2} = \frac{- 6 - 2 30}{2 \cdot 7}

p = \frac{- 6 + 2 30}{2 \cdot 7} : \frac{- 3 + 30}{7}

p = \frac{- 6 - 2 30}{2 \cdot 7} : - \frac{3 + 30}{7}

The solutions to the quadratic equation are:

p = \frac{- 3 + 30}{7}, p = - \frac{3 + 30}{7}

\frac{2}{3} m + 14 = 0

4 y^{3} - 4 y^{2} - 24 y

(2 x + 1)^{2} - (x - 2)^{2}

- \frac{5 π}{6} + 2 π

\frac{3}{2} \cdot \frac{1}{8}

What are the solutions to the equation 7p^2=-6p+3 ?
The solutions to the equation 7p^2=-6p+3 are p=(-3+sqrt(30))/7 ,p=-(3+sqrt(30))/7
Find the zeros of 7p^2=-6p+3
The zeros of 7p^2=-6p+3 are p=(-3+sqrt(30))/7 ,p=-(3+sqrt(30))/7