What is (sin(θ)+1)^2(cos(θ)-1)^2 ?

The solution to (sin(θ)+1)^2(cos(θ)-1)^2 is (sin(θ)+1)^2(cos(θ)-1)^2

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simplify (sin(θ)+1)^2(cos(θ)-1)^2

simplify

(sin (θ) + 1)^{2} (cos (θ) - 1)^{2}

(sin (θ) + 1)^{2} (cos (θ) - 1)^{2}

Solution steps

(sin (θ) + 1)^{2} (cos (θ) - 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(sin (θ) + 1)^{2} (cos (θ) - 1)^{2} = ((sin (θ) + 1) (cos (θ) - 1))^{2}

= ((sin (θ) + 1) (cos (θ) - 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (sin (θ) + 1)^{2} (cos (θ) - 1)^{2}

28 1 5^{14}

(2 x)^{3}

e^{- l n (2 x)}

\frac{- 14}{- 2}

5 t^{4}

What is (sin(θ)+1)^2(cos(θ)-1)^2 ?
The solution to (sin(θ)+1)^2(cos(θ)-1)^2 is (sin(θ)+1)^2(cos(θ)-1)^2