What are the solutions to the equation x^2-4x-77=0 ?

The solutions to the equation x^2-4x-77=0 are x=11,x=-7

Find the zeros of x^2-4x-77=0

The zeros of x^2-4x-77=0 are x=11,x=-7

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x^{2} - 4 x - 77 = 0

x = 11, x = - 7

Solution steps

x^{2} - 4 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 77 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 77) = 18

x_{1, 2} = \frac{- ( - 4 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 18}{2 \cdot 1}

x = \frac{- ( - 4 ) + 18}{2 \cdot 1} : 11

x = \frac{- ( - 4 ) - 18}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 11, x = - 7

3 x^{2} + 14 x + 11

8 x^{2} - 10 x y + 3 y^{2}

x^{2} - 4 x - 12 = 84

7 (x - 4)^{2} - 3 (x + 5)^{2} = 4 (x + 1) (x - 1) + 3

(4 9^{3})^{\frac{1}{6}}

What are the solutions to the equation x^2-4x-77=0 ?
The solutions to the equation x^2-4x-77=0 are x=11,x=-7
Find the zeros of x^2-4x-77=0
The zeros of x^2-4x-77=0 are x=11,x=-7