What is (p^5q^8r)(p^2q^3r^5)(p^4qr^3) ?

The solution to (p^5q^8r)(p^2q^3r^5)(p^4qr^3) is p^{11}q^{12}r^9

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simplify (p^5q^8r)(p^2q^3r^5)(p^4qr^3)

simplify

(p^{5} q^{8} r) (p^{2} q^{3} r^{5}) (p^{4} q r^{3})

p^{11} q^{12} r^{9}

Solution steps

(p^{5} q^{8} r) (p^{2} q^{3} r^{5}) (p^{4} q r^{3})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

p^{5} p^{2} p^{4} = p^{5 + 2 + 4}

= q^{8} r q^{3} r^{5} p^{5 + 2 + 4} q r^{3}

Add the numbers:

5 + 2 + 4 = 11

= q^{8} r q^{3} r^{5} p^{11} q r^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

q^{8} q^{3} q = q^{8 + 3 + 1}

= r r^{5} p^{11} q^{8 + 3 + 1} r^{3}

Add the numbers:

8 + 3 + 1 = 12

= r r^{5} p^{11} q^{12} r^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

r r^{5} r^{3} = r^{1 + 5 + 3}

= p^{11} q^{12} r^{1 + 5 + 3}

Add the numbers:

1 + 5 + 3 = 9

= p^{11} q^{12} r^{9}

(\frac{3}{5})^{6}

(2 x^{2}) (3 x^{3})

(\frac{81}{25})^{2}

\frac{5 - 2}{5 + 2}

What is (p^5q^8r)(p^2q^3r^5)(p^4qr^3) ?
The solution to (p^5q^8r)(p^2q^3r^5)(p^4qr^3) is p^{11}q^{12}r^9