What is (e^{-1/2})^2ln(e^{-1/2}) ?

The solution to (e^{-1/2})^2ln(e^{-1/2}) is -1/(2e)

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simplify (e^{-1/2})^2ln(e^{-1/2})

simplify

(e^{- \frac{1}{2}})^{2} ln (e^{- \frac{1}{2}})

- \frac{1}{2 e}

Decimal Notation

- 0.18393 \dots

Solution steps

(e^{- \frac{1}{2}})^{2} ln (e^{- \frac{1}{2}})

(e^{- \frac{1}{2}})^{2} : e^{- 1}

= e^{- 1} ln (e^{- \frac{1}{2}})

Simplify

ln (e^{- \frac{1}{2}}) : - \frac{1}{2}

= e^{- 1} (- \frac{1}{2})

Simplify

= - \frac{1}{2 e}

e^{- s t} \cdot e^{a t}

e^{- t} cos (3 t) u_{4 π} (t)

(1 + x)^{- 4}

\frac{- 55}{5}

I n e^{- 2}

What is (e^{-1/2})^2ln(e^{-1/2}) ?
The solution to (e^{-1/2})^2ln(e^{-1/2}) is -1/(2e)