What is (e^{-n^2-2n-1})/(e^{-n^2)} ?

The solution to (e^{-n^2-2n-1})/(e^{-n^2)} is e^{-2n-1}

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simplify (e^{-n^2-2n-1})/(e^{-n^2)}

simplify

\frac{e ^{- n^{2} - 2 n - 1}}{e ^{- n^{2}}}

e^{- 2 n - 1}

Solution steps

\frac{e ^{- n^{2} - 2 n - 1}}{e ^{- n^{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= e^{- n^{2} - 2 n - 1 - (- n^{2})}

Apply rule

- (- a) = a

= e^{- n^{2} - 2 n - 1 + n^{2}}

Simplify

- n^{2} - 2 n - 1 + n^{2} : - 2 n - 1

= e^{- 2 n - 1}

4 x^{128} x^{5} y^{7}

e^{- 2 l n (s i n (y))}

e^{2} (e - 1)^{2}

(5.5 \cdot 1 0^{8}) (2.1 \cdot 1 0^{- 15})

(e^{5 t})^{2}

What is (e^{-n^2-2n-1})/(e^{-n^2)} ?
The solution to (e^{-n^2-2n-1})/(e^{-n^2)} is e^{-2n-1}