What is 1/(sqrt(2pi))e^{-(0^2)/2} ?

The solution to 1/(sqrt(2pi))e^{-(0^2)/2} is 1/(2^{1/2)pi^{1/2}}

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simplify 1/(sqrt(2pi))e^{-(0^2)/2}

simplify

\frac{1}{2 π} e^{- \frac{0 ^{2}}{2}}

\frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

Decimal Notation

0.39894 \dots

Solution steps

\frac{1}{2 π} e^{- \frac{0 ^{2}}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{2 π} \cdot \frac{1}{e ^{\frac{0 ^{2}}{2}}}

Apply rule

0^{a} = 0

0^{2} = 0

= \frac{1}{2 π} \cdot \frac{1}{e ^{\frac{0}{2}}}

\frac{1}{2 π} = \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

= \frac{1}{e ^{\frac{0}{2}}} \cdot \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

\frac{1}{e ^{\frac{0}{2}}} = 1

= 1 \cdot \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

Multiply:

\frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}} \cdot 1 = \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

= \frac{1}{2 ^{\frac{1}{2}} π ^{\frac{1}{2}}}

(5 - 3) (5 + 6)

2.5 \cdot 1 0^{- 8}

2.5 \cdot 1 0^{- 9}

- e^{- x} (e^{- x})

3.6 \cdot 1 0^{- 2}

What is 1/(sqrt(2pi))e^{-(0^2)/2} ?
The solution to 1/(sqrt(2pi))e^{-(0^2)/2} is 1/(2^{1/2)pi^{1/2}}