What is 8.85*10^{-12}(4)(1/(6*10^7)-1/(10^7)) ?

The solution to 8.85*10^{-12}(4)(1/(6*10^7)-1/(10^7)) is (59)/(10^{20)}-(177)/(10^{19)*5}

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simplify 8.8510^{-12}(4)(1/(610^7)-1/(10^7))

simplify

8.85 \cdot 1 0^{- 12} (4) (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

\frac{59}{1 0 ^{20}} - \frac{177}{1 0 ^{19} \cdot 5}

Decimal Notation

0

Solution steps

8.85 \cdot 1 0^{- 12} (4) (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

Apply rule:

(a) = a

(4) = 4

= 8.85 \cdot 1 0^{- 12} \cdot 4 (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

Multiply the numbers:

8.85 \cdot 4 = 35.4

= 35.4 \cdot 1 0^{- 12} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

= 1 0^{- 12} \cdot 35.4 (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= \frac{1}{1 0 ^{12}} \cdot 35.4 (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

\frac{1}{1 0 ^{12}} \cdot 35.4 (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}}) = \frac{35.4}{1 0 ^{12}} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

= \frac{35.4}{1 0 ^{12}} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

\frac{35.4}{1 0 ^{12}} = \frac{354}{10 \cdot 1 0 ^{12}}

= \frac{354}{10 \cdot 1 0 ^{12}} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

Cancel

\frac{354}{10 \cdot 1 0 ^{12}} : \frac{177}{5 \cdot 1 0 ^{12}}

= \frac{177}{5 \cdot 1 0 ^{12}} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

Expand

\frac{177}{5 \cdot 1 0 ^{12}} (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}}) : \frac{59}{1 0 ^{20}} - \frac{177}{1 0 ^{19} \cdot 5}

= \frac{59}{1 0 ^{20}} - \frac{177}{1 0 ^{19} \cdot 5}

5 a \cdot 2 a (a^{3} - 3 a^{2} + a)

2 [e^{u}]_{1}^{2}

What is 8.85*10^{-12}(4)(1/(6*10^7)-1/(10^7)) ?
The solution to 8.85*10^{-12}(4)(1/(6*10^7)-1/(10^7)) is (59)/(10^{20)}-(177)/(10^{19)*5}