What is \sqrt[1!+2!+3!]{((8!)/(6!+7!))^{4!+2!+0!}} ?

The solution to \sqrt[1!+2!+3!]{((8!)/(6!+7!))^{4!+2!+0!}} is 343

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simplify \sqrt[1!+2!+3!]{((8!)/(6!+7!))^{4!+2!+0!}}

simplify

343

Solution steps

(\frac{8 !}{6 ! + 7 !})^{4! + 2! + 0!} = 7^{27}

1! + 2! + 3! = 9

Apply radical rule:

= 7^{\frac{27}{9}}

Divide the numbers:

\frac{27}{9} = 3

= 7^{3}

7^{3} = 343

= 343

5 e^{- (2)^{2}}

8 e^{- 1}

\frac{2}{15}

(9 y^{3}) (5 y^{3})

What is \sqrt[1!+2!+3!]{((8!)/(6!+7!))^{4!+2!+0!}} ?
The solution to \sqrt[1!+2!+3!]{((8!)/(6!+7!))^{4!+2!+0!}} is 343