What is t/2 e^{-((t-2)/2)}u((t-2)/2) ?

The solution to t/2 e^{-((t-2)/2)}u((t-2)/2) is (tu(t-2)}{4e^{\frac{t-2)/2}}

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simplify t/2 e^{-((t-2)/2)}u((t-2)/2)

simplify

\frac{t}{2} e^{- (\frac{t - 2}{2})} u (\frac{t - 2}{2})

\frac{t u ( t - 2 )}{4 e ^{\frac{t - 2}{2}}}

Solution steps

\frac{t}{2} e^{- (\frac{t - 2}{2})} u (\frac{t - 2}{2})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{t - 2}{2}}} \cdot \frac{t}{2} \cdot \frac{t - 2}{2} u

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{t \cdot 1 \cdot ( t - 2 ) u}{2 e ^{\frac{t - 2}{2}} \cdot 2}

Refine

= \frac{t u ( t - 2 )}{4 e ^{\frac{t - 2}{2}}}

(2 x) (3 x^{3}) (4 x^{2})

x 2

7.31 \cdot 1 0^{- 5}

(x - 1)^{2} \cdot x^{2}

What is t/2 e^{-((t-2)/2)}u((t-2)/2) ?
The solution to t/2 e^{-((t-2)/2)}u((t-2)/2) is (tu(t-2)}{4e^{\frac{t-2)/2}}