What is (n^{ln(4)})/((n+1)^{ln(4))} ?

The solution to (n^{ln(4)})/((n+1)^{ln(4))} is (n/(n+1))^{2ln(2)}

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simplify (n^{ln(4)})/((n+1)^{ln(4))}

simplify

\frac{n ^{l n (4)}}{( n + 1 ) ^{l n (4)}}

(\frac{n}{n + 1})^{2 l n (2)}

Solution steps

\frac{n ^{l n (4)}}{( n + 1 ) ^{l n (4)}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{n ^{l n (4)}}{( n + 1 ) ^{l n (4)}} = (\frac{n}{n + 1})^{l n (4)}

= (\frac{n}{n + 1})^{l n (4)}

Simplify

ln (4) : 2 ln (2)

= (\frac{n}{n + 1})^{2 l n (2)}

(e^{t})^{3}

\frac{- 6}{- 3}

x + 6 \cdot x - 4

4.5 x 1 0^{- 2}

What is (n^{ln(4)})/((n+1)^{ln(4))} ?
The solution to (n^{ln(4)})/((n+1)^{ln(4))} is (n/(n+1))^{2ln(2)}