What is (\sqrt[3]{2^{x+1}})^5 ?

The solution to (\sqrt[3]{2^{x+1}})^5 is 2^{x+1}(\sqrt[3]{2^{x+1}})^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (\sqrt[3]{2^{x+1}})^5

simplify

Solution steps

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply exponent rule:

assuming

n i s o dd or a \geq 0

t e^{- t} u (t)

e^{- l n (20 - t)}

222

(\frac{9 ^{2}}{9 ^{- 12}}) (\frac{9 ^{- 3}}{( - 9 ^{9} )})

What is (\sqrt[3]{2^{x+1}})^5 ?
The solution to (\sqrt[3]{2^{x+1}})^5 is 2^{x+1}(\sqrt[3]{2^{x+1}})^2