What is (e^{-7/12})^4ln(e^{-7/12}) ?

The solution to (e^{-7/12})^4ln(e^{-7/12}) is -7/(12e^{7/3)}

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simplify (e^{-7/12})^4ln(e^{-7/12})

simplify

(e^{- \frac{7}{12}})^{4} ln (e^{- \frac{7}{12}})

- \frac{7}{12 e ^{\frac{7}{3}}}

Decimal Notation

- 0.05656 \dots

Solution steps

(e^{- \frac{7}{12}})^{4} ln (e^{- \frac{7}{12}})

(e^{- \frac{7}{12}})^{4} : e^{- \frac{7}{3}}

= e^{- \frac{7}{3}} ln (e^{- \frac{7}{12}})

Simplify

ln (e^{- \frac{7}{12}}) : - \frac{7}{12}

= e^{- \frac{7}{3}} (- \frac{7}{12})

Simplify

= - \frac{7}{12 e ^{\frac{7}{3}}}

4 e^{- 2 (0)}

\frac{d}{d ( 1 )} ((10 e^{- 1}) (cos (π) 1))

(\frac{5}{2})^{2}

5 e^{- 2 t}

What is (e^{-7/12})^4ln(e^{-7/12}) ?
The solution to (e^{-7/12})^4ln(e^{-7/12}) is -7/(12e^{7/3)}