What is (7x^{1/3})(2x^{1/4}) ?

The solution to (7x^{1/3})(2x^{1/4}) is 14x^{7/12}

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simplify (7x^{1/3})(2x^{1/4})

simplify

(7 x^{\frac{1}{3}}) (2 x^{\frac{1}{4}})

14 x^{\frac{7}{12}}

Solution steps

(7 x^{\frac{1}{3}}) (2 x^{\frac{1}{4}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{\frac{1}{3}} x^{\frac{1}{4}} = x^{\frac{1}{3} + \frac{1}{4}}

= 7 \cdot 2 x^{\frac{1}{3} + \frac{1}{4}}

x^{\frac{1}{3} + \frac{1}{4}} = x^{\frac{7}{12}}

= 7 \cdot 2 x^{\frac{7}{12}}

Multiply the numbers:

7 \cdot 2 = 14

= 14 x^{\frac{7}{12}}

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What is (7x^{1/3})(2x^{1/4}) ?
The solution to (7x^{1/3})(2x^{1/4}) is 14x^{7/12}