What is expand log_{7}(h^2)(j)^{11}(k)^{-5} ?

The solution to expand log_{7}(h^2)(j)^{11}(k)^{-5} is (2j^{11}log_{7}(h))/(k^5)

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expand log_{7}(h^2)(j)^{11}(k)^{-5}

expand

lo g_{7} (h^{2}) (j)^{11} (k)^{- 5}

\frac{2 j ^{11} lo g _{7} ( h )}{k ^{5}}

Solution steps

lo g_{7} (h^{2}) (j)^{11} (k)^{- 5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= j^{11} \frac{1}{k ^{5}} lo g_{7} (h^{2})

Simplify

lo g_{7} (h^{2}) : 2 lo g_{7} (h)

= 2 j^{11} \frac{1}{k ^{5}} lo g_{7} (h)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 lo g _{7} ( h ) j ^{11}}{k ^{5}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 j ^{11} lo g _{7} ( h )}{k ^{5}}

e^{- 3 l n (5)}

\frac{13}{5}

e^{- 3 (2.5)}

\frac{d}{d x} (2 (x^{2} + y^{2})^{2})

e^{- 7 t}

What is expand log_{7}(h^2)(j)^{11}(k)^{-5} ?
The solution to expand log_{7}(h^2)(j)^{11}(k)^{-5} is (2j^{11}log_{7}(h))/(k^5)