What is ((1+3sqrt(2))^2-17)e^{-(1+3sqrt(2))} ?

The solution to ((1+3sqrt(2))^2-17)e^{-(1+3sqrt(2))} is (2+6sqrt(2))/(e^{1+3sqrt(2))}

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simplify ((1+3sqrt(2))^2-17)e^{-(1+3sqrt(2))}

simplify

((1 + 32)^{2} - 17) e^{- (1 + 32)}

\frac{2 + 6 2}{e ^{1 + 32}}

Decimal Notation

0.05542 \dots

Solution steps

((1 + 32)^{2} - 17) e^{- (1 + 32)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(1 + 32)}} ((1 + 32)^{2} - 17)

Remove parentheses:

(a) = a

= ((1 + 32)^{2} - 17) \frac{1}{e ^{1 + 32}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( ( 1 + 3 2 ) ^{2} - 17 )}{e ^{1 + 32}}

1 \cdot ((1 + 32)^{2} - 17) = (1 + 32)^{2} - 17

= \frac{( 1 + 3 2 ) ^{2} - 17}{e ^{1 + 32}}

Expand

(1 + 32)^{2} - 17 : 2 + 62

= \frac{2 + 6 2}{e ^{1 + 32}}

7.9 \cdot 1 0^{- 12}

(x + 5)^{2} (x - 5)^{2}

\frac{x ^{2}}{( x - 3 ) ^{2}}

What is ((1+3sqrt(2))^2-17)e^{-(1+3sqrt(2))} ?
The solution to ((1+3sqrt(2))^2-17)e^{-(1+3sqrt(2))} is (2+6sqrt(2))/(e^{1+3sqrt(2))}