What is (x-4)(x+3)(x-1)^2(x+2)(x-5)^2(x+6) ?

The solution to (x-4)(x+3)(x-1)^2(x+2)(x-5)^2(x+6) is (x-1)^2(x-5)^2(x-4)(x+3)(x+2)(x+6)

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simplify (x-4)(x+3)(x-1)^2(x+2)(x-5)^2(x+6)

simplify

(x - 4) (x + 3) (x - 1)^{2} (x + 2) (x - 5)^{2} (x + 6)

(x - 1)^{2} (x - 5)^{2} (x - 4) (x + 3) (x + 2) (x + 6)

Solution steps

(x - 4) (x + 3) (x - 1)^{2} (x + 2) (x - 5)^{2} (x + 6)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x - 1)^{2} (x - 5)^{2} = ((x - 1) (x - 5))^{2}

= (x - 4) (x + 3) ((x - 1) (x - 5))^{2} (x + 2) (x + 6)

((x - 1) (x - 5))^{2} = (x - 1)^{2} (x - 5)^{2}

= (x - 4) (x + 3) (x - 1)^{2} (x - 5)^{2} (x + 2) (x + 6)

a^{2} x^{2}

4 x^{- 0.5}

2 x e^{- 3 x}

3500000 (1 + (\frac{0.31}{4}))^{- 4}

What is (x-4)(x+3)(x-1)^2(x+2)(x-5)^2(x+6) ?
The solution to (x-4)(x+3)(x-1)^2(x+2)(x-5)^2(x+6) is (x-1)^2(x-5)^2(x-4)(x+3)(x+2)(x+6)