What is the answer to 3(z+3)=7+3z+6-z ?

The answer to 3(z+3)=7+3z+6-z is z=4

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3(z+3)=7+3z+6-z

3 (z + 3) = 7 + 3 z + 6 - z

z = 4

Solution steps

3 (z + 3) = 7 + 3 z + 6 - z

Group like terms

3 (z + 3) = 3 z - z + 7 + 6

Add similar elements:

3 z - z = 2 z

3 (z + 3) = 2 z + 7 + 6

Add the numbers:

7 + 6 = 13

3 (z + 3) = 2 z + 13

Expand

3 (z + 3) : 3 z + 9

3 z + 9 = 2 z + 13

Move

9

to the right side

3 z = 2 z + 4

Move

2 z

to the left side

z = 4

\frac{a}{6} = \frac{15}{2}

(3 e^{2} - 5 e + 7) (6 e + 1)

x^{2} \leq 169

- 2 i^{4}

3 (y - 5) - 5 y = 2 y + 9